Engineering Quantitative Aptitude English Reasoning General Knowledge Coding Others

Quiz: Percentage

To View Tricks: Login Required

Number of Questions: 44

Question: 1 -

Rahul went to a shop and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?

Options:

  1. Rs. 16.80

  2. Rs. 12.10

  3. Rs. 15

  4. Rs. 19.70

    5. Answer:

    Rs. 19.70
    Solution:

    tax = 30 paise = Rs.0.3
    tax is 6%.
    i.e., Rs.0.3 is 6% of the taxable item.
    Therefore, cost of taxable item =(0.3×100)/6=5
    cost of the tax free items =25−(0.3+5)=19.7

Question: 2 -

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?

Options:

  1. 44, 33

  2. 42, 36

  3. 44, 36

  4. 42, 33

    5. Answer:

    42, 33
    Solution:

    Let the marks secured by them be x and (x+9)
    sum of their marks =x+(x+9)=2x+9
    Given that (x+9) was 56% of the sum of their marks.
    ⇒(x+9)=(56/100)(2x+9)⇒(x+9)=(14/25)(2x+9)⇒25x+225=28x+126⇒3x=99⇒x=33
    Then (x+9)=33+9=42
    Hence their marks are 33 and 42

Question: 3 -

Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?

Options:

  1. Rs. 250

  2. Rs. 150

  3. Rs. 300 

  4. Rs. 200

    5. Answer:

    Rs. 250
    Solution:

    amount paid to X per week =x and the amount paid to Y per week =y
    Then x+y=550  â‹¯(1)
    But x=120% of y =120y/100=12y/10  â‹¯(2)
    From (1) and (2)
    (12y/10)+y=550⇒22y/10=550⇒y=5500/22=500/2=250

Question: 4 -

Two numbers A and B are such that the sum of 5% of A and 4% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio of A : B.

Options:

  1. 2:1

  2. 4:3

  3. 1:2

  4. 1:1

    5. Answer:

    4:3
    Solution:

    5% of A + 4% of B =(2/3)(6% of A + 8% of B)
    => (5A/100)+(4B/100)=(2/3)(6A100+8B100)
    => 5A + 4B =(2/3)(6A+ 8B)
    => 15A + 12B = 12A+ 16B
    => 3A = 4B
    => A : B = 4 : 3

Question: 5 -

The population of a town increased from 1,75,000 to 2,62,500 in a decade. What is the average percent increase of population per year?

Options:

  1. 50%

  2. 4%

  3. 5%

  4. 6%

    5. Answer:

    5%
    Solution:

    increase in the population in 10 years
    =262500−175000=87500
    percent increase in the population in 10 years
    =(87500/175000)×100=8750/175=50%
    average percent increase of population per year
    =50%/10=5%